![how to mount an 2n3055 transistor how to mount an 2n3055 transistor](https://htmlimg2.alldatasheet.com/htmldatasheet2/394672/NI/USB-6212/56/2/USB-6212.png)
Anything more than 5mA will kill the Transistor hence a resistor is always added in series with base pin. As mentioned the biasing current should maximum of 5mA. As discussed a transistor will act as an Open switch during Forward Bias and as a Closed switch during Reverse Bias, this biasing can be achieved by supplying the required amount of current to the base pin. When a transistor is used as a switch it is operated in the Saturation and Cut-Off Region as explained above. When base current is removed the transistor becomes fully off, this stage is called as the Cut-off Region and the Base Emitter voltage could be around 660 mV. This stage is called Saturation Region and the typical voltage allowed across the Collector-Emitter (V CE) or Base-Emitter (V BE) could be 200 and 900 mV respectively. When this transistor is fully biased then it can allow a maximum of 100mA to flow across the collector and emitter. To bias a transistor we have to supply current to base pin, this current (I B) should be limited to 5mA. The maximum amount of current that could flow through the Collector pin is 100mA, hence we cannot connect loads that consume more than 100mA using this transistor. Note: Complete Technical Details can be found at the BC547 datasheet given at the end of this page.īC549, BC636, BC639, 2N2222 TO-92, 2N2222 TO-18, 2N2369, 2N3055, 2N3904, 2N3906, 2SC5200īC547 transistor has a gain value of 110 to 800, this value determines the amplification capacity of the transistor. Continuous Collector current (I C) is 100mA.Other capacitances should be negligible for your use.BC547 is a NPN transistor hence the collector and emitter will be left open (Reverse biased) when the base pin is held at ground and will be closed (Forward biased) when a signal is provided to base pin. Although the IRLU8726 would probably be a lot cooler.Īs stated a small gate resistor might be a good idea for PWM use to reduce current draw from the MCU a bit, the value of 150ohms seems okay and is not critical, use something between 150 and 470 and you should be fine. With an ambient of 20C, that would give a temperature just under 70C which should be quite safe at that current where the maximum allowable case temperature is about 155C. 77W at 10A which will mean a rise in temperature of about 48C degrees C over ambient. With an R DS ot 0.077ohms will give about. The dissipation would be the IRL540 should work but it will get a little hot. Hi dc42, no offense intended here, but I think you made a little error on the math. Look for a mosfet with much lower Rds(on), such as IRLU8726PBF (0.008 ohms max). IRL540 is not a good mosfet to use for switching 10A, its Rds(on) is 0.077 ohms max so it will dissipate around 7.7W when carrying 10A. With Faraday's law, the delta-T is in the denominator, so the less time it takes for the magnetic field to collapse, the higher the voltage is. The energy is the same, the "delta-T" is much smaller. The SAME energy (less losses) that you put into the rubber band stretching it is returned when you release it, but because it's faster, the "snap" stings your skin. When you let go of the top, the rubber band will snap DOWN (negative) very fast. Say you hold the bottom of the rubber band and stretch the top end higher and higher (more and more "positive"). So, normally the diode does nothing (reverse biased), But if an inductive kickback occurs, the diode is forward biased and "snubs" the spike. the PWM goes to the "off" cycle), the magnetic field collapses and can generate hundreds to thousands of volts in the OPPOSITE direction. So, if you put +12 volts into the motor, when you de-energize it (i.e. Faraday's law basically says that the faster a magnetic field changes, the higher the voltage induced in the wire. When the current is removed, the magnetic field collapses almost instantly. When the motor is energized, a magnetic field forms on the armature. What the diode does is protect the 2N3055 from inductive kickback. The resistors you highlighted are not necessary.
![how to mount an 2n3055 transistor how to mount an 2n3055 transistor](http://tostratonic.com/store/597-large_default/transistor-2n3055.jpg)
What should be the values?Īlso: what is the functionality of the 1N4007 diode next to the motor? And do I need to put another diode from the collector to the emitter of the 3055? I don't know if I need the two green resistors (with question marks), I didn't use them in the test but I saw that some people use them. The circuit works but I'm not sure that is perfectly ok. In the picture you can see that I'm using a 2n2222 that controls a TIP3055 (or a 2N3055).
#How to mount an 2n3055 transistor full
I need to control the speed of a dc motor (0.5 A no load, to 10 A full load).